Was digging into my laptop and found this Truss program written in python. Computes, displacement, stresses and reactions.

"""
Created on Thu May 08 07:07:24 2014
@author: Sukhbinder Singh
Truss FEM
"""
from __future__ import division
import numpy as np
modE=30.0e6
Area=2.0
#numElem=3
#numNodes=4
elemNodes=np.array([[0,1],[0,2],[0,3]])
nodeCords=np.array([[0.0,0.0],[0.0,120.0],[120.0,120.0],[120.0,0]])
#'''
elemNodes=np.array([[0,1],[0,2],[1,2],[1,3],
[0,3],[2,3],[2,5],[3,4],[3,5],[2,4],[4,5]])
nodeCords=np.array([
[0.0,0.0],[0.0,3000.0],
[3000.0,0.0],[3000.0,3000.0],
[6000.0,0.0],[6000.0,3000.0]
])
modE=70000
Area=300
#'''
numElem=elemNodes.shape[0]
numNodes=nodeCords.shape[0]
xx=nodeCords[:,0]
yy=nodeCords[:,1]
EA=modE*Area
tdof = 2*numNodes #total number of degrees of freedom
disps=np.zeros((tdof,1))
force=np.zeros((tdof,1))
sigma=np.zeros((numElem,1))
stiffness=np.zeros((tdof,tdof))
np.set_printoptions(precision=3)
'''
force[1]=-10000.0
presDof=np.arange(2,9)
'''
force[3]=-50000.0
force[7]=-100000.0
force[11]=-50000.0
presDof=np.array([0,1,9])
#'''
for e in xrange(numElem):
indice= elemNodes[e,:]
elemDof=np.array([indice[0]*2, indice[0]*2+1, indice[1]*2, indice[1]*2+1 ])
xa=xx[indice[1]]-xx[indice[0]]
ya=yy[indice[1]]-yy[indice[0]]
len_elem=np.sqrt(xa*xa+ya*ya)
c=xa/len_elem
s=ya/len_elem
k1=(EA/len_elem)* np.array([[c*c,c*s,-c*c, -c*s],
[c*s,s*s,-c*s ,-s*s],
[-c*c,-c*s,c*c,c*s],
[-c*s,-s*s,c*s,s*s]])
stiffness[np.ix_(elemDof,elemDof)] +=k1
actDof=np.setdiff1d(np.arange(tdof),presDof)
disp1=np.linalg.solve(stiffness[np.ix_(actDof,actDof)],force[np.ix_(actDof)]);
disps[np.ix_(actDof)]=disp1
# stresses at elements
for e in xrange(numElem):
indice= elemNodes[e,:]
elemDof=np.array([indice[0]*2, indice[0]*2+1, indice[1]*2, indice[1]*2+1 ])
xa=xx[indice[1]]-xx[indice[0]]
ya=yy[indice[1]]-yy[indice[0]]
len_elem=np.sqrt(xa*xa+ya*ya)
c=xa/len_elem
s=ya/len_elem
sigma[e] = (modE/len_elem) * np.dot(np.array([-c,-s,c,s]),disps[np.ix_(elemDof)])
print disps
print sigma
react = np.dot(stiffness,disps)
print react.reshape((numNodes,2))

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